The explanations for all ten questions sit on this sheet. Pick an answer on the left and the matching card lights up.
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G2A01 Explanation 1
Key B — About 44,000 ohms
XL = 2 pi f L = 2 x 3.1416 x 3.5 x 10^6 x 0.002 = 43,982 ohms. Doubling the inductance or the frequency doubles the reactance, so the halved answers correspond to 1 mH or 1.75 MHz.
Rule Fundamentals - inductive reactance
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G2A02 Explanation 2
Key A — About 455 ohms
XC = 1 / (2 pi f C) = 1 / (2 x 3.1416 x 3.5 x 10^6 x 100 x 10^-12) = 455 ohms. Because capacitance is in the denominator, a larger capacitor has less reactance.
Rule Fundamentals - capacitive reactance
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G2A03 Explanation 3
Key D — f = 1 / (2 pi sqrt(L C))
The resonant frequency is inversely proportional to the square root of the product of inductance and capacitance. Note the shape of the relationship: quadrupling either L or C halves the resonant frequency.
Rule Fundamentals - resonance
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G2A04 Explanation 4
Key C — It falls to a minimum, equal to the circuit resistance
At series resonance the reactances cancel, leaving only resistance and giving maximum current. A parallel resonant circuit behaves the opposite way, presenting a high impedance at resonance.
Rule Fundamentals - series resonance
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G2A05 Explanation 5
Key B — 70.7 volts
RMS is peak divided by the square root of 2, so 100 / 1.414 = 70.7 V. Going the other way, 120 V RMS mains has a peak of about 170 V.
Rule Fundamentals - RMS and peak
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G2A06 Explanation 6
Key A — 800 ohms
Impedance changes as the square of the turns ratio: 50 x 4^2 = 800 ohms. Multiplying by 4 rather than 16 gives the 200 ohm trap answer.
Rule Fundamentals - transformer impedance transformation
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G2A07 Explanation 7
Key D — A band-pass filter
Only a band-pass rejects on both sides of a wanted range. A low-pass would admit the lower-frequency broadcast signal, a high-pass would admit harmonics, and a notch would remove the band you want.
Rule 47 CFR §97.307 - harmonic suppression
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G2A08 Explanation 8
Key C — In series with the circuit
Current is measured by putting the meter in the current path, so the same current flows through it - in series. Connecting an ammeter across a supply shorts it, because an ideal ammeter has almost no resistance.
Rule Fundamentals - measurements
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G2A09 Explanation 9
Key B — It decreases, in proportion to the square root of the capacitance
Since f = 1 / (2 pi sqrt(LC)), capacitance is under the square root in the denominator: quadrupling C halves f. That is exactly how a variable capacitor tunes a receiver across a band.
Rule Fundamentals - resonance
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G2A10 Explanation 10
Key B — It adds impedance to common-mode current on the shield without affecting the wanted differential signal
A clamp-on ferrite is a lossy inductance for current flowing on the outside of the shield - the common-mode path that causes RF in the shack and distorted patterns. Signal current inside the coax, flowing in opposite directions on centre and shield, largely cancels in the core.
Rule 47 CFR §97.13(c) - RF exposure and good engineering practice